Report Issue

JEE MAIN 2025
24-01-2025 SHIFT-1
Question
The Young's double slit interference experiment is performed using light consisting of 480 nm and 600 nm wavelengths to form interference patterns. The least number of the bright fringes of 480 nm light that are required for the first coincidence with the bright fringes formed by 600 mm light is
Select the correct option:
A
4
B
8
C
5
D
6
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\frac{{{n_1}{\lambda _1}D}}{d} = \frac{{{n_2}{\lambda _2}D}}{d}$
$n480 = m600$
${n_{\min }} = 5$
Question Tags
JEE Main
Physics
Easy
Start Preparing for JEE with Competishun
Video Solution
BY competishun
Video Solution
Watch Solution