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JEE MAIN 2019
12-04-2019 S2
Question
Thermal decomposition of a Mn compound $(\mathrm{X})$ at 513 K results in compound $\mathrm{Y}, \mathrm{MnO}_2$ and a gaseous product. $\mathrm{MnO}_2$ reacts with NaCl and concentrated $\mathrm{H}_2 \mathrm{SO}_4$ to give a pungent gas $\mathrm{Z} . \mathrm{X}, \mathrm{Y}$ and Z respectively are:
Select the correct option:
A
$\mathrm{K}_2 \mathrm{MnO}_4, \mathrm{KMnO}_4$ and $\mathrm{Cl}_2$
B
$\mathrm{K}_3 \mathrm{MnO}_4, \mathrm{~K}_2 \mathrm{MnO}_4$ and $\mathrm{Cl}_2$
C
$\mathrm{K}_2 \mathrm{MnO}_4, \mathrm{KMnO}_4$ and $\mathrm{SO}_2$
D
$\mathrm{KMnO}_4, \mathrm{~K}_2 \mathrm{MnO}_4$ and $\mathrm{Cl}_2$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Chemistry
Easy
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