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JEE MAIN 2023
8-4-23_S1
Question
Three bulbs are filled with CH4, CO2 and Ne as shown in the picture. The bulbs are connected through pipes of zero volume. When the stopcocks are opened and the temperature is kept constant throughout, the pressure of the system is found to be_______ atm. (Nearest integer)
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Solution
Sol. $\quad \mathrm{P}_{\mathrm{TV}}=\mathrm{ntR}^{\circ}$ For $\mathrm{CH}_4$ $$ \begin{aligned} & 2 \times 2=n_1 R T \\ & \Rightarrow n_1=\frac{4}{R T} \end{aligned} $$ For $\mathrm{CO}_2$ $$ \Rightarrow \mathrm{n}_2=\frac{12}{\mathrm{RT}} $$ For Ne $$ \begin{aligned} & \left.\Rightarrow n_3=\frac{12}{R T} \right\rvert\, \\ & \Rightarrow n_T=\frac{1}{R T}[4+12+12]=\frac{28}{R T} \\ & P_T=\frac{28}{R T} \frac{R T}{V_T} \\ & P_T=\frac{28}{V_T}=3.11 \end{aligned} $$
Question Tags
JEE Main
Chemistry
Medium
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