Report Issue

JEE Advanced 2024
Paper-1 2024
Question
Two beads, each with charge q and mass m, are on a horizontal, frictionless, non-conducting, circular hoop of radius R. One of the beads is glued to the hoop at some point, while the other one performs small oscillations about its equilibrium position along the hoop. The square of the angular frequency of the small oscillations is given by [ $\varepsilon_0$ is the permittivity of free space.]
Select the correct option:
A
$q^2 /\left(4 \pi \varepsilon_0 R^3 m\right)$
B
$q^2 /\left(32 \pi \varepsilon_0 R^3 m\right)$
C
$q^2 /\left(8 \pi \varepsilon_0 R^3 m\right)$
D
$q^2 /\left(16 \pi \varepsilon_0 R^3 m\right)$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Advance
Physics
Hard
Start Preparing for JEE with Competishun