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JEE MAIN 2021
24-02-2021 S2
Question
Two electrons each are fixed at a distance '2d'. A third charge proton placed at the midpoint is displaced slightly by a distance x (x << d) perpendicular to the line joining the two fixed charges. Proton will execute simple harmonic motion having angular frequency : (m = mass of charged particle)
Select the correct option:
A
$\left(\frac{2 q^2}{\pi \varepsilon_0 m d^3}\right)^{\frac{1}{2}}$
B
$\left(\frac{\pi \varepsilon_0 m d^3}{2 q^2}\right)^{\frac{1}{2}}$
C
$\left(\frac{q^2}{2 \pi \varepsilon_0 m d^3}\right)^{\frac{1}{2}}$
D
$\left(\frac{2 \pi \varepsilon_0 m d^3}{q^2}\right)^{\frac{1}{2}}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Physics
Medium
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