Two ideal polyatomic | KTG & THERMODYNAMICS

JEE_MAIN2021

_170321_S1

Question

Two ideal polyatomic gases at temperatures $\mathrm{T}_1$ and $\mathrm{T}_2$ are mixed so that there is no loss of energy. If $F_1$ and $F_2, m_1$ and $m_2, n_1$ and $n_2$ be the degrees of freedom, masses, number of molecules of the first and second gas respectively, the temperature of mixture of these two gases is:

Select the correct option:

$\frac{n_1 T_1+n_2 T_2}{n_1+n_2}$

$\frac{n_1 F_1 T_1+n_2 F_2 T_2}{n_1 F_1+n_2 F_2}$

$\frac{n_1 F_1 T_1+n_2 F_2 T_2}{F_1+F_2}$

$\frac{n_1 F_1 T_1+n_2 F_2 T_2}{n_1+n_2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution