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JEE MAIN 2023
11-4-2023
Question
Two identical cells each of emf 1.5 V are connected in series across a $10 \Omega$ resistance. An ideal voltmeter connected across $10 \Omega$ resistance reads 1.5 V . the internal resistance of each cell is $\_\_\_\_$ $\Omega$.
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Solution
$\begin{aligned} & \text { Sol. } \quad \begin{aligned} V & =I \times 10 \\ 1.5 & =\left(\frac{3}{10+2 r}\right) \times 10 \\ r & =5 \Omega .\end{aligned} \\ & \\ & \end{aligned}$
Question Tags
JEE Main
Chemistry
Easy
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