EMF JEE Main 2025 Solution | Magnetic Field Wires Problem

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JEE MAIN 2025

22-01-2025 SHIFT-2

Question

Two long parallel wires $X$ and $Y$, separated by a distance of 6 cm , carry currents of 5 A and 4A, respectively, in opposite directions as shown in the figure. Magnitude of the resultant magnetic field at point P at a distance of 4 cm from wire Y is $x \times 10^{-5} \mathrm{~T}$. The value of $x$ is $\_\_\_\_$ Take permeability of free space as $\mu_0=4 \pi \times 10^{-7}$ Sl units.

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Consider the lines $$ \begin{aligned} & L_1: \frac{x+1}{3}=\frac{y+2}{1}=\frac{z+1}{2} \\ & L_2: \frac{x-2}{1}=\frac{y+2}{2}=\frac{z-3}{3} \end{aligned} $$
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