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JEE MAIN 2021
25-02-2021 S2
Question
Two particles having masses 4 g and 16 g respectively are moving with equal kinetic energies. The ratio of the magnitudes of their linear momentum is n : 2. The value of n will
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Solution
$\begin{aligned} & \frac{p_1^2}{2 \times 4}=\frac{p_2^2}{2 \times 16} \\ & \frac{p_1}{p_2}=\frac{1}{2}\end{aligned}$
Question Tags
JEE Main
Physics
Easy
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