Two particles move at right angle |MODERNPHYSICSJEEMain2019

JEE MAIN 2019

08-04-2019 S1

Question

Two particles move at right angle to each other. Their de Broglie wavelengths are $\lambda_1$ and $\lambda_2$ respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelength $\lambda$, of the final particle, is given by:

Select the correct option:

$\lambda=\sqrt{\lambda_1 \lambda_2}$

$\lambda=\frac{\lambda_1+\lambda_2}{2}$

$\frac{2}{\lambda}=\frac{1}{\lambda_1}+\frac{1}{\lambda_2}$

$\frac{1}{\lambda^2}=\frac{1}{\lambda_1^2}+\frac{1}{\lambda_2^2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Medium

Start Preparing for JEE with Competishun

Report Issue