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JEE MAIN 2025
22-01-2025 SHIFT-1
Question
Two soap bubbles of radius 2 cm and 4 cm , respectively, are in contact with each other. The radius of curvature of the common surface, in cm , is _______ .
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Solution
Answer 4
${\rm{r}} = \frac{{{{\rm{r}}_1} \cdot {{\rm{r}}_2}}}{{{{\rm{r}}_1} - {{\rm{r}}_2}}} = \frac{{2 \cdot 4}}{{4 - 2}} = 4\;{\rm{cm}}$
Question Tags
JEE Main
Physics
Easy
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