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JEE MAIN 2025
08-04-2025 S2
Question
Two strings with circular cross section and made of same material, are stretched to have same amount of tension. A transverse wave is then made to pass through both the strings. The velocity of the wave in the first string having the radius of cross section R is $v_1$, and that in the other string having radius of cross section $\mathrm{R} / 2$ is $v_2$. Then $\frac{v_2}{v_1}=$
Select the correct option:
A
8
B
4
C
$\sqrt{2}$
D
2
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & v=\sqrt{\frac{T}{\mu}}=\sqrt{\frac{T}{f \pi R^2}} \\ & \frac{v_2}{v_1}=\frac{R_1}{R_2}=2\end{aligned}$
Question Tags
JEE Main
Physics
Easy
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