Report Issue

JEE ADVANCED 2025
Paper-2 2025
Question
A temperature difference can generate e.m.f. in some materials. Let S be the e.m.f. produced per unit temperature difference between the ends of a wire, $\sigma$ the electrical conductivity and k the thermal conductivity of the material of the wire. Taking M, L, T, I and K as dimensions of mass, length, time, current and temperature, respectively, the dimensional formula of the quantity $Z=\frac{S^2 \sigma}{\kappa}$ is:
Select the correct option:
A
$\left[M^0 L^0 T^0 I^0 K^0\right]$
B
$\left[M^0 L^0 T^0 I^0 K^{-1}\right]$
C
$\left[M^1 L^2 T^{-2} I^{-1} K^{-1}\right]$
D
$\left[M^1 L^2 T^{-4} I^{-1} K^{-1}\right]$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Advance
Physics
Easy
Start Preparing for JEE with Competishun