Volume of 3 MNaOH formula weight|Mole Concept|JEEMAIN-2024

JEE MAIN 2024

27-01-24 S2

Question

Volume of 3 MNaOH (formula weight $40 \mathrm{~g} \mathrm{~mol}^{-1}$ ) which can be prepared from 84 g of NaOH is × $10^{-1} \mathrm{dm}^3$.

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JEE Main

Chemistry

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