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JEE MAIN 2019
10-04-2019 S2
Question
Water from a tap emerges vertically downwards with an initial speed of $1.0 \mathrm{~ms}^{-1}$. The crosssectional area of the tap is $10^{-4} \mathrm{~m}^2$. Assume that the pressure is constant throughout the stream of water and that the flow is streamlined. The crosssectional area of stream, 0.15 m below the tap would be: $$ \left(\text { Take } \mathrm{g}=10 \mathrm{~ms}^{-2}\right) $$
Select the correct option:
A
$1 \times 10^{-5} \mathrm{~m}^2$
B
$5 \times 10^{-5} \mathrm{~m}^2$
C
$5 \times 10^{-4} \mathrm{~m}^2$
D
$2 \times 10^{-5} \mathrm{~m}^2$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Question Tags
JEE Main
Physics
Hard
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