Ionic Equilibrium | JEE Main 2025 Solution

JEE MAIN 2025

24-01-2025 SHIFT-1

Question

$\;{{\rm{K}}_{{\rm{sp }}}}$ for ${\rm{Cr}}{({\rm{OH}})_3}$ is $1.6 \times {10^{ - 30}}$. What is the molar solubility of this salt in water?

Select the correct option:

$\sqrt[5]{{1.8 \times {{10}^{ - 30}}}}$

$\sqrt[2]{{1.6 \times {{10}^{ - 30}}}}$

$\sqrt[4]{{\frac{{1.6 \times {{10}^{ - 30}}}}{{27}}}}$

$\frac{{1.8 \times {{10}^{ - 30}}}}{{27}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Chemistry

Easy

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