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JEE MAIN
26.02.2021_S2
Question
When 12.2 g of benzoic acid is dissolved in 100 g of water, the freezing point of solution was found to be $-0.93^{\circ} \mathrm{C}\left(\mathrm{K}_f\left(\mathrm{H}_2 \mathrm{O}\right)=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right)$. The number $(\mathrm{n})$ of benzoic acid molecules associated (assuming 100\% association) is $\_\_\_\_$ .
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Question Tags
JEE Main
Chemistry
Easy
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