When 9.45 g of $\mathrm{ClCH}_2 \mathrm{COOH}$ is added to 500 mL of water, its freezing point drops by $0.5^{\circ} \mathrm{C}$. The dissociation constant of $\mathrm{ClCH}_2 \mathrm{COOH}$ is $\mathrm{x} \times 10^{-3}$. The value of x is $\_\_\_\_$ .
(Rounded off to the nearest integer)
$
\left[\mathrm{K}_{\mathrm{f}\left(\mathrm{H}_2 \mathrm{O}\right)}=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right]
$
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇