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JEE MAIN_2025
030425_S2
Question
Width of one of the two slits in a Young's double slit interference experiment is half of the other slit. The ratio of the maximum to the minimum intensity in the interference pattern is :
Select the correct option:
A
$(2 \sqrt{2}+1):(2 \sqrt{2}-1)$
B
$3: 1$
C
$(3+2 \sqrt{2}):(3-2 \sqrt{2})$
D
9 : 1
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Easy
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