Let for some $\alpha \in \mathrm{i}, f: \mathrm{i} \rightarrow \mathrm{i}$ be a function satisfying $f(x+y)=f(x)+2 y^2+y+\alpha x y$ for all $x, y \in \mathrm{i}$. If $f(0)=-1$ and $f(1)=2$, then the value of $\sum_{n=1}^5(\alpha+f(n))$ is:
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