Consider the following reaction at 298" " K.
$\frac{3}{2} \mathrm{O}_{2(\mathrm{~g})} \rightleftharpoons \mathrm{O}_{3(\mathrm{~g})} \cdot \mathrm{K}_{\mathrm{p}}=2.47 \times 10^{-29}$
$\Delta_{\mathrm{r}} \mathrm{G}^{\Theta}$ for the reaction is $\_\_\_\_$ $\mathrm{kJ} .\left(\right.$ Given $\left.\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)$
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