A Proton, an Electron and... |JEE Main 2024

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JEE MAIN 2024

09-04-24 S1

Question

A proton, an electron and an alpha particle have the same energies. Their de-Broglie wavelengths will be compared as:

Select the correct option:

$\lambda_e>\lambda_\alpha>\lambda_p$

$\lambda_\alpha<\lambda_p<\lambda_e$

$\lambda_p>\lambda_e>\lambda_\alpha$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & \lambda_{\mathrm{DB}}=\frac{\mathrm{h}}{\mathrm{p}}=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mk}}} \\ & \Rightarrow \lambda_{\mathrm{DB}} \alpha \frac{1}{\sqrt{\mathrm{~m}}} \\ & \Rightarrow \lambda_{\mathrm{a}}<\lambda_{\mathrm{p}}<\lambda_{\mathrm{e}}\end{aligned}$

Question Tags

JEE Main

Physics

Easy

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