Uniform electric field of 10 N/C is created

JEE MAIN 2023

25.01.23

Question

A uniform electric field of 10 N/C is created between two parallel charged plates (as shown in figure). An electron enters the field symmetrically between the plates with a kinetic energy 0.5 eV. The length of each plate is 10 cm. The angle () of deviation of the path of electron as it comes out of the field is ___ (in degree

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Solution

Sol. $$ \begin{aligned} & 0.5 e=\frac{1}{2} m v_x^2 \Rightarrow v_x=\sqrt{\frac{e}{m}} \\ & \text { Along } x L=v_x t=\sqrt{\frac{e}{m}} t \\ & \text { Along } y v_y=\frac{e}{m} t \\ & \text { dividing } \frac{v_y}{L}=E_{\sqrt{ }} \sqrt{\frac{e}{m}}=E v_x \\ & \Rightarrow \tan \theta=\frac{v_y}{v_x}=E \times L=10 \times 0.1=L \\ & \qquad \theta=45^{\circ} \end{aligned} $$

Question Tags

JEE Main

Physics

Easy

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