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JEE MAIN 2023
08-04-23 S1
Question
For a nucleus ${ }_Z^A X$ having mass number $A$ and atomic number $Z$
A. The surface energy per nucleon $\left(\mathrm{b}_{\mathrm{s}}\right)=\mathrm{a}_1 \mathrm{~A}^{2 / 3}$
B. The Coulomb contribution to the binding energy $b_c=-a_2 \frac{Z(Z-1)}{A^{4 / 3}}$
C. The volume energy $\mathrm{b}_{\mathrm{v}}=\mathrm{a}_3 \mathrm{~A}$
D. Decrease in the binding energy is proportional to surface area.
E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons, (a1, $\mathrm{a}_2$ and $\mathrm{a}_3$ are constants)
Choose the most appropriate answer from the options given below:
Select the correct option:
A
C, D only
B
B, C, E only
C
A, B, C, D only
D
B, C only
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Medium
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