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JEE MAIN 2024
31.01.24 S2
Question
Light from a point source in air falls on a convex curved surface of radius 20 cm and refractive index 1.5. If the source is located at 100 cm from the convex surface, the image will be formed at cm from the object.
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Solution
$$ \begin{aligned} & \frac{\mu_2}{\mathrm{v}}-\frac{\mu_1}{\mathrm{u}}=\frac{\mu_2-\mu_1}{\mathrm{R}} \\ & \frac{1.5}{\mathrm{v}}-\frac{1}{-100}=\frac{1.5-1}{20} \\ & \mathrm{v}=100 \mathrm{~cm} \end{aligned} $$ Distance from object $$ \begin{aligned} & =100+100 \\ & =200 \mathrm{~cm} \end{aligned} $$
Question Tags
JEE Main
Physics
Easy
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