The relation between | KTG & THERMODYNAMICS

JEE MAIN 2023

25-06-2022 S1

Question

The relation between root mean square speed $\left(v_{\mathrm{rms}}\right)$ and most probable speed $\left(v_p\right)$ for the molar mass $M$ of oxygen gas molecule at the temperature of 300 K will be :-

Select the correct option:

$v_{\mathrm{rms}}=\sqrt{\frac{2}{3}} v_{\mathrm{p}}$

$\mathrm{v}_{\mathrm{rms}}=\sqrt{\frac{3}{2}} \mathrm{v}_{\mathrm{p}}$

$V_{\mathrm{rms}}=V_p$

$v_{r m s}=\sqrt{\frac{1}{3}} v_p$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$$ v_{r m s}=\sqrt{\frac{3 R T}{M}} \text { and } v_{m p}=\sqrt{\frac{2 R T}{M}} $$ Thus $\mathrm{v}_{\mathrm{rms}}=\sqrt{\frac{3}{2}} \mathrm{v}_{\mathrm{mp}}$

Question Tags

JEE Main

Physics

Easy

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