A steam engine. |CALORIMETRY AND THERMAL EXPANSION|JEE-MAIN

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JEE MAIN 2022

25-06-2022 S1

Question

A steam engine intakes 50 g of steam at $100^{\circ} \mathrm{C}$ per minute and cools it down to $20^{\circ} \mathrm{C}$. If latent heat of vaporization of steam is $540 \mathrm{cal} \mathrm{g}^{-1}$, then the heat rejected by the steam engine per minute is $\_\_\_\_$ $\times 10^3$ cal.

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Solution

$\begin{aligned} & \text { Heat rejected }=m L_f+m S \Delta T \\ & =(50 \times 540)+50(1)(100-20) \\ & =31000 \mathrm{Cal} \\ & =31 \times 10^3 \mathrm{Cal}\end{aligned}$

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