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JEE MAIN 2022
28-07-2022 S2
Question
The products obtained during treatment of hard water using Clark's method are:
Select the correct option:
A
$\mathrm{CaCO}_3$ and $\mathrm{MgCO}_3$
B
$\mathrm{Ca}(\mathrm{OH})_2$ and $\mathrm{Mg}(\mathrm{OH})_2$
C
$\mathrm{CaCO}_3$ and $\mathrm{Mq}(\mathrm{OH})_2$
D
$\mathrm{Ca}(\mathrm{OH})_2$ and $\mathrm{MgCO}_3$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
In Clark's method lime water is used $$ \begin{aligned} & \mathrm{Ca}\left(\mathrm{HCO}_3\right)_2+2 \mathrm{Ca}(\mathrm{OH})_2 \rightarrow 2 \mathrm{CaCO}_3+2 \mathrm{H}_2 \mathrm{O} \\ & \mathrm{Mg}\left(\mathrm{HCO}_3\right)_2+2 \mathrm{Ca}(\mathrm{OH})_2 \rightarrow 2 \mathrm{CaCO}_3+\mathrm{Mg}(\mathrm{OH})_2+2 \mathrm{H}_2 \mathrm{O} \end{aligned} $$
Question Tags
JEE Main
Chemistry
Easy
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