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JEE MAIN 2022
29-07-2022 S2
Question
When borax is heated with CoO on a platinum loop, blue coloured bead formed is largely due to:
Select the correct option:
A
$\mathrm{B}_2 \mathrm{O}_3$
B
$\mathrm{Co}\left(\mathrm{BO}_2\right)_2$
C
$\mathrm{CoB}_4 \mathrm{O}_7$
D
$\mathrm{Co}\left[\mathrm{B}_4 \mathrm{O}_5(\mathrm{OH})_4\right]$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$$ \begin{aligned} & \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 10 \mathrm{H}_2 \mathrm{O} \xrightarrow{\Delta} \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7+10 \mathrm{H}_2 \mathrm{O} \\ & \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \xrightarrow{\Delta} 2 \mathrm{NaBO}_2 \text { (sodium metaborate) }+\mathrm{B}_2 \mathrm{O}_3 \\ & \mathrm{~B}_2 \mathrm{O}_3+\mathrm{CoO} \rightarrow \mathrm{Co}\left(\mathrm{BO}_2\right)_2 \text { (cobalt (II) meta borate) } \end{aligned} $$ Blue Bead
Question Tags
JEE Main
Chemistry
Easy
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