The $\mathrm{NaNO}_3$ weighed out to make 50 mL of an aqueous solution containing $70.0 \mathrm{mg} \mathrm{Na}^{+}$per mL is $\_\_\_\_$ g. (Rounded off to the nearest integer)
[Given : Atomic weight in $\mathrm{g} \mathrm{mol}^{-1}-\mathrm{Na}: 23 ; \mathrm{N}: 14 ; \mathrm{O}: 16$ ]
