Particle executing | SIMPLE HARMONIC MOTION | JEE MAIN_2026

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JEE MAIN_2026

06-04-26_S1

Question

A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec. The time required by it to move from $\mathrm{x}=\mathrm{A}$ to $x=\frac{A}{\sqrt{2}}$ is $\_\_\_\_$ sec.

Select the correct option:

A

1/4

B

5/4

C

5/8

D

3/8

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

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