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JEE-MAIN 2021
17-03-2021 S2
Question
The velocity of a particle is $\mathrm{v}=\mathrm{v}_0+\mathrm{gt}+\mathrm{Ft}^2$. Its position is $\mathrm{x}=0$ at $\mathrm{t}=0$; then its displacement after time $(\mathrm{t}=1)$ is :
Select the correct option:
A
$\mathrm{v}_0+\mathrm{g}+\mathrm{F}$
B
$v_0+\frac{g}{2}+\frac{F}{3}$
C
$v_0+\frac{g}{2}+F$
D
$\mathrm{v}_0+2 \mathrm{~g}+3 \mathrm{~F}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Easy
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