Binomial Theorem_JEE MAIN 2021_180321_S1 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE MAIN 2021

18-03-21 S1

Question

Let $\left(1+x+2 x^2\right) 20=a_0+a_1 x+a_2 x_2+\ldots+a_{40} x^{40}$. then $\mathbf{a}_1+\mathbf{a}_3+\mathbf{a}_5+\ldots+\mathbf{a}_{37}$ is equal to

Select the correct option:

$2^{20}\left(2^{20}-21\right)$

$2^{19}\left(2^{20}-21\right)$

$2^{19}\left(2^{20}+21\right)$

$2^{20}\left(2^{20}+21\right)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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