The energy released in the fusion of 2 kg of hydrogen deep in the sun is $\mathrm{E}_{\mathrm{H}}$ and the energy released in the fission of 2 kg of ${ }^{235} \mathrm{U}$ is $\mathrm{E}_{\mathrm{U}}$. The ratio $\frac{E_H}{E_U}$ is approximately :
(Consider the fusion reaction as $4{ }_1^1 \mathrm{H}+2 \mathrm{e}^{-} \rightarrow{ }_2^4 \mathrm{He}+2 \mathrm{v}+6 \gamma+26.7 \mathrm{MeV}$, energy released in the fission reaction of ${ }^{235} \mathrm{U}$ is 200 MeV per fission nucleus and $N_A=6.023 \times 10^{23}$ )