Report Issue

JEE MAIN 2021
24-02-2021 S2
Question
Sucrose hydrolyses in acid solution into glucose and fructose following first order rate law with a half-life of 3.33 h at $25^{\circ} \mathrm{C}$. After 9 h , the fraction of sucrose remaining is $f$. The value of $\log _{10}\left(\frac{1}{f}\right)$ is $\_\_\_\_$ $\times 10^{-2}$. (Rounded off to the nearest integer) [Assume : In $10=2.303, \ln 2=0.693$ ]
Write Your Answer
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Chemistry
Medium
Start Preparing for JEE with Competishun