Let $f: R \rightarrow R$ be defined as $f(x)=\left\{\begin{array}{cl}\frac{\lambda\left|x^2-5 x+6\right|}{\mu\left(5 x-x^2-6\right)}, & x<2 \\ e^{\frac{\operatorname{an}(x-2)}{x-14}}, & x>2 . \text { where }[x] \text { is the greatest integer less than or } \\ \mu, & x=2\end{array}\right.$ equal to $x$. If $f$ is continuous at $x=2$, then $\lambda+\mu$ is equal to $i$