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JEE MAIN 2020
07-01-20 S1
Question
A 60 HP electric motor lifts an elevator having a maximum total load capacity of 2000 kg . If the frictional force on the elevator is 4000 N , the speed of the elevator at full load is close to : $(1 \mathrm{HP}=746 \left.\mathrm{W}, \mathrm{g}=10 \mathrm{~ms}^{-2}\right)$
Select the correct option:
A
$1.5 \mathrm{~ms}^{-1}$
B
$1.9 \mathrm{~ms}^{-1}$
C
$1.7 \mathrm{~ms}^{-1}$
D
$2.0 \mathrm{~ms}^{-1}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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