Permutations Combinations JEE Main Solution

JEE MAIN 2025

22-01-2025 SHIFT-2

Question

In a group of 3 girls and 4 boys, there are two boys $B_1$ and $B_2$. The number of ways, in which these girls and boys can stand in a queue such that all the girls stand together, all the boys stand together, but $B_1$ and $B_2$ are not adjacent to each other, is :

Select the correct option:

120

144

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

\begin{aligned} &\text { Total - when } B_1 \text { and } B_2 \text { are together }\\ &=2!(3!4!)-2!(3!(3!2!))=144 \end{aligned}

Question Tags

JEE Main

Mathematics

Easy

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