Combustion of 1 mole of benzene is expressed at
$$
\mathrm{C}_6 \mathrm{H}_6(1)+\frac{15}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+3 \mathrm{H}_2 \mathrm{O}(1) .
$$
The standard enthalpy of combustion of 2 mol of benzene is - ' x ' kJ .
$$
\mathbf{X}=
$$
$\_\_\_\_$ .
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