The pitch and the number of...|MODERN PHYSICS|JEEMAIN 2019

JEE MAIN 2019

09-01-19 S2

Question

The pitch and the number of divisions, on the circular scale, for a given screw gauge are 0.5 mm and 100 respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line.
The readings of the main scale and the circular scale, for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is:

Select the correct option:

5.725 mm

5.740 mm

5.755mm

5.950 mm

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

LC = 0.5 / 100 = 0.005 mm Zero error, e = −3 × 0.005 = −0.015 mm Thickness = (5.5 + 48 × 0.005 − 0.015) mm = 5.725 mm

Question Tags

JEE Main

Physics