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JEE MAIN 2023
23-01-2025 SHIFT-1
Question
Let P be the foot of the perpendicular from the point $Q(10, - 3, - 1)$ on the line $\frac{{x - 3}}{7} = \frac{{y - 2}}{{ - 1}} = \frac{{z + 1}}{{ - 2}}$ . Then the area of the right angled triangle P Q R, where R is the point (3,–2,1), is
Select the correct option:
A
$8\sqrt {15} $
B
$\sqrt {30} $
C
$3\sqrt {30} $
D
$9\sqrt {15} $
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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