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JEE MAIN 2020
02-09-2020 S2
Question
For the disproportionation reaction $2 \mathrm{Cu}^{+}(\mathrm{ag}) \rightleftharpoons \mathrm{Cu}(\mathrm{s})+\mathrm{Cu}^{2+}(\mathrm{ag})$ at $298 \mathrm{~K} . \mathrm{In} \mathrm{K}$ (where K is the equilibrium constant) is $\_\_\_\_$ $\times 10^{-1}$. Given : $$ \left(\mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}^{+}}^0=0.16 \mathrm{~V} ; \quad \mathrm{E}_{\mathrm{Cu}^{+} / \mathrm{Ou}}^0=0.52 \mathrm{~V} ; \frac{\mathrm{RT}}{\mathrm{~F}}=0.025\right) $$
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Question Tags
JEE Main
Chemistry
Easy
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