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JEE Advanced 2025
PAPER-2 2025
Question
Let $a_0, a_1, \ldots, a_{23}$ be real numbers such that
$ \left(1+\frac{2}{5} x\right)^{23}=\sum_{i=0}^{23} a_i x^i $
for every real number $x$. Let $a_r$ be the largest among the numbers $a_j$ for $0 \leq j \leq 23$.
Then the value of $r$ is $\_\_\_\_$
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Question Tags
JEE Advance
Mathematics
Easy
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