Let us consider an endothermic reaction which is non-spontaneous at the freezing point of water. However, the reaction is spontaneous at boiling point of water. Choose the correct option.
Select the correct option:
A
Both $\Delta {\rm{H}}$ and $\Delta {\rm{S}}$ are (-ve)
B
$\Delta {\rm{H}}$ is ( -ve ) but $\Delta {\rm{S}}$ is (+ve)
C
Both $\Delta {\rm{H}}$ and $\Delta {\rm{S}}$ are (+ve)
D
$\Delta {\rm{H}}$ is ( +ve ) but $\Delta {\rm{S}}$ is (-ve)
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Reaction is spontaneous at relatively high temperature and non-spontaneous at low temperature $\Delta {\rm{G}} = \Delta {\rm{H}} - {\rm{T}}\Delta {\rm{S}}$
It is only possible when $\Delta {\rm{H}}$ and $\Delta {\rm{S}}$ both are positive
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