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JEE MAIN 2025
23-01-2025 SHIFT-2
Question
A satellite of mass $\frac{M}{2}$ is revolving around earth in a circular orbit at a height of $\frac{R}{3}$ from earth surface. The angular momentum of the satellite is $\mathrm{M} \sqrt{\frac{\mathrm{GMR}}{x}}$. The value of $x$ is
$\_\_\_\_$ , where $M$ and $R$ are the mass and radius of earth, respectively.
( G is the gravitational constant)
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JEE Main
Physics
Easy
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