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JEE MAIN_2026
04-04-26_S2
Question
In a screw gauge when the circular scale is given five complete rotations it moves linearly by 2.5 mm. If the circular scale has 100 divisions, the least count of screw gauge is ____ mm.
Select the correct option:
A
$1 \times 10^{-2}$
B
$1 \times 10^{-3}$
C
$5 \times 10^{-2}$
D
$5 \times 10^{-3}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & \text { Pitch } \Rightarrow \frac{2.5 \mathrm{~mm}}{5}=0.5 \mathrm{~mm}=5 \times 10^{-4} \mathrm{~m} \\ & \text { L.C. } \Rightarrow \frac{\text { Pitch }}{\text { No. of divisions }}=\frac{5 \times 10^{-4}}{100} \mathrm{~m} \\ & =5 \times 10^{-6} \mathrm{~m} \\ & =5 \times 10^{-3} \mathrm{~mm}\end{aligned}$
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