Gravitation | JEE Main 2025 Solution

JEE MAIN 2025

28-01-2025 SHIFT-2

Question

Earth has mass 8 times and radius 2 times that of a planet. If the escape velocity from the earth is $11.2 \mathrm{~km} / \mathrm{s}$, the escape velocity in $\mathrm{km} / \mathrm{s}$ from the planet will be :

Select the correct option:

8.4

5.6

11.2

2.8

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\mathrm{V}_{\text {escape }}=\sqrt{\frac{2 \mathrm{GM}}{\mathrm{R}}}$
$\frac{\left(\mathrm{V}_{\text {escape }}\right)_{\text {Planet }}}{\left(\mathrm{V}_{\text {escape }}\right)_{\text {Earth }}}=\sqrt{\left(\frac{\mathrm{M}_{\mathrm{P}}}{\mathrm{M}_{\mathrm{E}}}\right) \times\left(\frac{\mathrm{R}_{\mathrm{E}}}{\mathrm{R}_{\mathrm{P}}}\right)}=\frac{1}{2} ;\left(\mathrm{V}_{\text {escape }}\right)_{\text {Planet }}=\frac{1}{2}\left(\mathrm{~V}_{\text {escape }}\right)_{\text {Earth }}=5.6 \mathrm{~km} / \mathrm{s}$

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JEE Main

Physics

Medium

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