A particle of mass m is moving in the... | Laws of Motion

JEE Advanced 2023

Paper-1 2023

Question

A particle of mass $m$ is moving in the $x y$-plane such that its velocity at a point $(x, y)$ is given as $\vec{v}=a(y \hat{x}+2 x \hat{y})$, where $a$ is $\alpha$ non-zero constant. What is the force $\vec{F}$ acting on the particle?

Select the correct option:

$\vec{F}=2 m a^2(x \hat{x}+y \hat{y})$

$\vec{F}=m a^2(y \hat{x}+2 x \hat{y})$

$\vec{F}=2 m a^2(y \hat{x}+x \hat{y})$

$\vec{F}=m a^2(x \hat{x}+2 y \hat{y})$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Advance

Physics

Easy

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