Area Under Curve | JEE Main 2025 Solution

JEE MAIN 2025

28-01-2025 SHIFT-2

Question

The area of the region bounded by the curves $x\left(1+y^{2}\right)=1$ and $y^{2}=2 x$ is:

Select the correct option:

$\frac{1}{2}\left(\frac{\pi}{2}-\frac{1}{3}\right)$

$\frac{\pi}{2}-\frac{1}{3}$

$2\left(\frac{\pi}{2}-\frac{1}{3}\right)$

$\frac{\pi}{4}-\frac{1}{3}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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