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JEE MAIN 2025
29-01-2025 SHIFT-2
Question
Let $y^{2}=12 x$ be the parabola and $S$ be its focus. Let PQ be a focal chord of the parabola such that $(S P)(S Q)=\frac{147}{4}$. Let $C$ be the circle described taking PQ as a diameter. If the equation of a circle $C$ is $64 x^{2}+64 y^{2}-\alpha x-64 \sqrt{3} y=\beta$, then $\beta-\alpha$ is equal to $\_\_\_\_$ .
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Question Tags
JEE Main
Mathematics
Medium
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